A. Two complementary angles are x+20 and 2x-56 degrees. i. The value o

1.	A. Two complementary angles are x+20 and 2x-56 degrees. i. The value of x = ___ degrees. *I. 42ii. 40iii. 44
Answer» → Correct Question : TWO complementary angles are (x + 20) and (2x - 56) degrees ,then find the value of x . → To Find : The value of x... → Given : Given the two complementary angles , $\mathtt{(x + 20)}$ $\mathtt{(2x - 56)}$ → We Know : The sum of two complementary angles are 90°. → Concept : As we know that the sum of two complementary angles are 90° and the sides are given , i.e , (x + 20) and (2x - 56)°. So the equation formed is , $\boxed{\mathtt{\therefore (x + 20)° + (2x - 56)° = 90°}}$ → Solution : Given Equation : $\mathtt{(x + 20)° + (2x - 56)° = 90°}$ By solving this solution, we GET : $\mathtt{\Rightarrow x + 20° + 2x - 56° = 90°}$ $\mathtt{\Rightarrow 3x - 36° = 90°}$ $\mathtt{\Rightarrow 3x = 90° + 36°}$ $\mathtt{\Rightarrow 3x = 126°}$ $\mathtt{\Rightarrow x = \dfrac{126°}{3}}$ $\mathtt{\Rightarrow x = \dfrac{\cancel{126°}}{\cancel{3}}}$ $\mathtt{\Rightarrow x = 42°}$ HENCE ,the value of x is 42°. *The answer is option (i)...* → Additional information : Sum of two supplementary angles = 180° Heron's formula : $\mathtt{\sqrt{s(s - a)(s - b)(s - c)}}$ Where, a,b, and c are the sides of the SCALENE triangle ... s = semi-perimeter $s = \dfrac{a + b + c}{2}$ Area of Equilateral triangle = $\dfrac{\sqrt{3}a^{2}}{4}$ Area of isosceles triangle = $\dfrac{1}{4}b\sqrt{4a - b}$