1.

A tunnel is dug through the centre of the earth. Show that a body of mass m when dropped from rest from one end of the tunnel will execute simple harmonic motion.

Answer»

SOLUTION :SUPPOSE a body of MASS m reaches at point P with depth d from the surface of earth and P point at distance r from the centre of earth. So there is no force exerted on body of mass m from EXTERNAL part at the distance r from earth but force is exerted only by a mass of earth of radius r.

ACCELERATION due to gravity at depth d from the surface of earth
`g. = g(1-(d)/(R ))= g((R-d)/(R ))`
Let `R- d = y`,
`g. = (gy)/(R )`
Force on a body of mass m at point P,
`F= -mg.""` (force is considered negative toward the centre)
`F= -(mg)/(R )*y"""........."(1)`
`therefore F propto -y`
Now, `ma= -(mg)/(R )y""` (From equation (1))
`therefore a= -(g)/(R )y"""........."(2)`
comparing this equation `a= -omega^(2)y` with (2)(acceleration of SHM oscillator)
`omega^(2) = (g)/(R )`
`therefore omega = sqrt((g)/(R ))`
`therefore (2pi)/(T)= sqrt((g)/(R ))`
`therefore T= 2pi sqrt((R )/(g))`.


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