Saved Bookmarks
| 1. |
A tunnel is dug along the diameter of the earth. The gravitational force on particle of mass m placed in the tunnel at a distance .x. from the centre . |
|
Answer» Solution :MASS of EARTH `M=4/3 piR^(3)rho` Mass of imaginary sphere, having radiu x, `M^(1)=4/3pix^3rho("or")M^(1)/M=x^3/R^3` `:.` GRAVITATIONAL force on .m. DUE to `M_1` `F=(GM^1m)/x^2("or") F=(Gm)/x^2(x^3/R^3M)=(GMmx)/R^3`
|
|