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A tuning fork vibrating with a sonometer wire of length 20cm produces 5 beats per second. The beat frequency does not change if the length of the wire is changed to 21cm. The frequency of the tuning fork must be |
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Answer» Answer: Fundamental frequency is: n = 1/2l √T/m n 1/l assume for 20CM frequency is n1 and for 21 CM frequency is n2 So n1/n2 = 21/20 then n1 = 21x and n2 = 20x Let frequency NF for producing 5 beats so n1 > nf > n2 So n1 - nf = 5 21x - nf = 5 ....(i) And nf - n2 = 5 nf - 20x = 5 .....(ii) from (1) ans (2) we GET x = 205 hz |
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