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a tube wells pumps out 3000 Kg of water per minute , if water is coming out with a velocity of 5m/s , what is the power of the pump ? |
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Answer» velocity ( v ) = 5 m/s mass of the water pumped =3000/60 m = 50 kg/s K.E. of water coming out per second = 1/2mv^2 = 1/2* 50 * 25 = 625 JOULE per second = 625 WATT . |
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