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A truck starts from rest. It travels a distance of 400m in 20s . Find its acceleration . Find the force acting on it if its mass is 7000

Answer»

velocity (u) = 0 m/s. --(At rest) Distance travelled (s) = 400mTime TAKEN (t) = 20sMass (m) = 7000 kgAcceleration (a) Force (F) Now, On using 2nd EQUATION of motion, we GET, ➦ s = UT +1/2 at²➭ 400 = 0×20 + 1/2a × (20)²➭ 400 = a/2 × 400➭ 400 = 400a/2➭ 400 = 200a➭ a = 400/200➭ a = 2m/s²Hence, Acceleration (a) = 2 m/s²Now, We know that, ➦ Force = Mass × Acceleration ➦ F = m × aOn putting above values in it, we get, ➭ F = 7000 × 2➭ F = 14000 NHence, Force(F) = 14000 Newtons



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