a truck ccelerates from 24m/s at constant rate 2.1m/s2 for 15sec. what

1.	a truck ccelerates from 24m/s at constant rate 2.1m/s2 for 15sec. what is the final speed of the car at the end of the 15seconds.
Answer» Answer: 55.55 m/s Explanation: Given : INITIAL velocity = u = 24 m/s Acceleration of the truck = a = 2.1 m/s² Time taken = t = 15 seconds To find : Final velocity of the truck after 15 seconds USING the first EQUATION of motion : V=u+at V=24+(2.1×15) V=24+31.5 V=55.5 m/s The final velocity of the truck after 15 seconds is equal to 55.55 m/s More : First equation of motion = v = u+at Second equation of motion = s = ut+½×at² Third equation of motion = v²-u²=2as

a truck ccelerates from 24m/s at constant rate 2.1m/s2 for 15sec. what is the final speed of the car at the end of the 15seconds.

Answer»

Answer:

55.55 m/s

Explanation:

Given :

INITIAL velocity = u = 24 m/s

Acceleration of the truck = a = 2.1 m/s²

Time taken = t = 15 seconds

To find :

Final velocity of the truck after 15 seconds

USING the first EQUATION of motion :

V=u+at

V=24+(2.1×15)

V=24+31.5

V=55.5 m/s

The final velocity of the truck after 15 seconds is equal to 55.55 m/s

More :

First equation of motion = v = u+at

Second equation of motion = s = ut+½×at²

Third equation of motion = v²-u²=2as

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a truck ccelerates from 24m/s at constant rate 2.1m/s2 for 15sec. what is the final speed of the car at the end of the 15seconds.​

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a truck ccelerates from 24m/s at constant rate 2.1m/s2 for 15sec. what is the final speed of the car at the end of the 15seconds.