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A trolley containing a liquid slides down a smooth inclined plane of angle `alpha` with the horizontal. Find the angle of inclination `theta` of the free surface with the horizontal. |
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Answer» The acceleration of the trolley is `a=gsintheta` down the inclined plane `a_(x)=acosalpha=(gsinalpha)cosalpha` `a_(y)=asinalpha=(gsinalpha)sinalpha=gsin^(2)alpha` Let `theta` be the angle made by free surface of liquid, then `tantheta=(a_(x))/(g-a_(y))=(gsinalphacosalpha)/(g-gsin^(2)alpha)=tanalpha` `theta=alpha` |
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