A triangular wire frame (each side =2m) is placed in a region of time variant magnetic field `dB//dt = (sqrt3) T//s`. The magnetic field is perpendicular to the plane of the triangle and its centre coincides with the centre of triangle. The base of the triangle AB has a resistance `1(Omega)` while the other two sides have resistance `2(Omega)` each. The magnitude of potential difference between the points A and B will be A. `0.4 V`B. `0.6 V`C. `1.2 V`D. None

A triangular wire frame (each side =2m) is placed in a region of time

1.	A triangular wire frame (each side =2m) is placed in a region of time variant magnetic field `dB//dt = (sqrt3) T//s`. The magnetic field is perpendicular to the plane of the triangle and its centre coincides with the centre of triangle. The base of the triangle AB has a resistance `1(Omega)` while the other two sides have resistance `2(Omega)` each. The magnitude of potential difference between the points A and B will be A. `0.4 V`B. `0.6 V`C. `1.2 V`D. None
Answer» Correct Answer - B `P.D` in the loop `= int vec(E).d vec(l) = (d phi)/(dt) = A(dB)/(dt)` `i = (Delta V)/(R_(T))" " R_(T) = 5 Omega , V_(AB) = iR_(AB)`

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