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A triangular colourful scenery is made on a wall with sides 25cm, 25cm and 40cm. A golden thread is to hang from the vertex so as to just reach the side 40cm perpendicularly. How much length of the golden thread is required? * |
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Answer» ong>Solution :- Given that, sides of TRIANGULAR colourful scenery are 25cm, 25cm and 40cm. As we can SEE two sides are 25cm each . Therefore, we can conclude that, the scenery is in the shape of a Isosceles TRIANGLE with two sides as 25cm and base as 40cm. Now, we know that, Perpendicular on base of a isosceles triangle bisect the base into two equal parts. So, By pythagoras theorem we get, → (Perpendicular)² + (Base/2)² = (Equal side)² Putting value as Base = 40cm and Equal side as 25cm , we get, → (Perpendicular)² + (40/2)² = (25)² → (Perpendicular)² + (20)² = (25)² → (Perpendicular)² + 400 = 625 → (Perpendicular)² = 625 - 400 → (Perpendicular)² = 225 → (Perpendicular)² = (15)² Square - root both sides now, we get, → Perpendicular = 15 cm. (Ans.) Hence, length of the golden thread is 15cm. |
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