A triangular block of mass M rests on a smooth surface as shown in figure. A cubical block of mass m rests on the inclined surface. If all surfaces are frictionless, the force that must be applied to M along horizontal direction so as tokeep m stationary relative to M is :

A triangular block of mass M rests on a smooth surface as shown in fig

1.	A triangular block of mass M rests on a smooth surface as shown in figure. A cubical block of mass m rests on the inclined surface. If all surfaces are frictionless, the force that must be applied to M along horizontal direction so as tokeep m stationary relative to M is :
Answer» The answer is F = (M +m)gtanθ Explanation:In this case, M and m are moving with the same acceleration "a". Note that a is along horizontal i.e. x-DIRECTION only. For M and m : F - N2Sinθ = ma .....(1) mg - N2Cosθ = 0 => N2 = mg/Cosθ ......(2) N2 Sinθ = ma ...(3) From equation (2) and (3) we can say that a = gtanθ By SUBSTITUTING equation (3) into (1) we obtain. F = (M +m)a F = (M +m)gtanθ Thus the force that must be applied to M along horizontal direction is F = (M +m)gtanθ .

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A triangular block of mass M rests on a smooth surface as shown in figure. A cubical block of mass m rests on the inclined surface. If all surfaces are frictionless, the force that must be applied to M along horizontal direction so as tokeep m stationary relative to M is :​

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A triangular block of mass M rests on a smooth surface as shown in figure. A cubical block of mass m rests on the inclined surface. If all surfaces are frictionless, the force that must be applied to M along horizontal direction so as tokeep m stationary relative to M is :