A triangle is formed by joining the coordinates B(0,0), C(8,0) and A(4,8). DE is joined where D is the mid-point of AB, and E is the mid-point of AC. DC and BE are joined to intersect at F. Then, Area of Δ DCB = n2 × Area of Δ EBC, where n is an integer. The value of n is __.

A triangle is formed by joining the coordinates B(0,0), C(8,0) and A(4

1.	A triangle is formed by joining the coordinates B(0,0), C(8,0) and A(4,8). DE is joined where D is the mid-point of AB, and E is the mid-point of AC. DC and BE are joined to intersect at F. Then, Area of Δ DCB = n2 × Area of Δ EBC, where n is an integer. The value of n is __.
Answer» A triangle is formed by joining the coordinates B(0,0), C(8,0) and A(4,8). DE is joined where D is the mid-point of AB, and E is the mid-point of AC. DC and BE are joined to intersect at F. Then, Area of $Δ$ DCB = $\frac{n}{2}$ $\times$ Area of $Δ$ EBC, where n is an integer. The value of n is __.