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A travelling wave is described by the equation `y = y_(0) sin ((ft - (x)/lambda))`. The maximum particle velocity is equal to four times the wave velocity ifA. `lamda = pi (y_0)/(4)`B. `lamda = pi (y_0)/(2)`C. `lamda = pi y_0`D. `lamda = 2 pi y_0` |
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Answer» Correct Answer - B `y = y_(0) sin 2 pi [ft-(x)/(lamda)]` `:. (dy)/(dt)=[y_(0) cos 2 pi(ft -(x)/(lamda))] xx 2 pi f` `rArr [(dy)/(dt)]_(max) = y_(0) xx 2pi f` Given that the maximum particle velocity is equal to four times the wave velocity `(c = f lamda)` `:. y_(0) xx 2pi f = 4 f xx lamda` `lamda = (pi y_(0))/(2)`. |
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