1.

A transverse wve given by Y = 0.021 sin (x + 30t) is propagating in a string of linear density 1.3 x, 10^(-4) kg/m. If x and y are in metres and time in seconds , the tension in string is :

Answer»

2.4 N
1.2 N
0.12 N
240 N

Solution :y = 0.021 sin (x + 30t)
here w = 30 rad /sec . And k = 1
`therefore V = (w)/(k) = (30)/(1) = 30 ms^(-1)`
Now in strings v = `sqrt((T)/(m))`
`therefore T = v^(2) .m = 900 xx 1.3 xx 10^(4) = 117 xx 10^(3) = 0.12 N `
hence the correct choice is (C).


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