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A transverse sinusoidal wave of amplitude `a`, wavelength `lambda` and frequency `f` is travelling on a stretched string. The maximum speed of any point in the string is `v//10`, where `v` is the speed of propagation of the wave. If `a = 10^(-3)m` and `v = 10ms^(-1)`, then `lambda` and `f` are given byA. `lamda = 2 pi xx 10^-2 m`B. `lamda = 10^-3 m`C. `f = (10^3)/(2 pi) Hz`D. `f = 10^4 Hz` |
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Answer» Correct Answer - A::C For a transverse sinusoidal wave travelling on a string the maximum velocity is `a omega`. Also, the maximum velocity is `(v)/(10)=(10)/(10) =1m//s` `:. a omega =1 rArr 10^(-3) xx 2 pi f=1` `rArr f =(1)/(2pi xx 10^(-3)) =(10^(3))/(2 pi) Hz` The velocity `v = f lamda` `:. lamda = (v)/(f) =(10)/(10^(3)//2pi) = 2pi xx 10^(-2) m`. |
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