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A transformer working on a 240 V AC supplies a voltage of 8 V to an electric bell in the circuit. The number of turns in the primary coil is 4800. Calculate the number of turns in the secondary coil. |
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Answer» Vp = 240V Vs = 8V Np = 4800 \(\cfrac{V_s}{V_p}\) = \(\cfrac{N_s}{N_p}\) Ns = \(\cfrac{V_s\times N_s}{240}\) = 160 |
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