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A transformer has an efficiency of 80%. It works at 4 kW, 100 V. If the secondary voltage is 240 V, Calculate the primary and secondary currents. |
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Answer» Here, `eta = 80%, P_(i) = 4 kW = 4000 watt, E_(p) = 100 V, E_(s) = 240 V, I_(p) = ? I_(s) = ?` As `P_(i) = E_(p) I_(p) :. I_(p) = (P_(i))/(E_(p)) = (4000)/(100) = 40 A` As `eta = (E_(s) I_(s))/(E_(p) I_(p)) :. (80)/(100) = (240 I_(s))/(4000) :. I_(s) = (80 xx 4000)/(100 xx 240) = 13.3 A` |
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