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A transformer has 500 turns in the primary and 1000 turns in its secondary. The primary voltage is 200 V and load in secondary is 100 ohm. Calculate the current in primary assuming it to ideal transformer. |
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Answer» Here, `n_(p) = 500, n_(s) = 1000` `E_(p) = 200 V, R_(s) = 100 Omega, I_(p) = ?` In an ideal transformer, `(E_(s))/(E_(p)) = (n_(s))/(n_(p)) = (1000)/(500) = 2`, `E_(s) = 2 E_(p) = 2 xx 200 = 400 V` Also, `(I_(p))/(I_(s)) = (n_(s))/(n_(p)) = 2`, `I_(p) = 2 I_(s) = 2 ((E_(s))/(R_(s))) = (2 xx 400)/(100) = 8 A` |
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