A trainacelerated from 10 km/her to 40 km/hin a 2 minutes. how much di

1.	A trainacelerated from 10 km/her to 40 km/hin a 2 minutes. how much distance would itan this period
Answer» $u = 10 \: km {}^{ - 1} = 2.7 \: ms {}^{ - 1}$ $v = 40 \: km {}^{ - 1} = 11.1 \: \: ms {}^{ - 1}$ $t = 2 \: minutes = 120 \: sec$ $a = ?$ $a = \frac{v - u}{t}$ $a = \frac{11.1 - 2.7}{120}$ $\huge\pink{\boxed{\purple{a = 0.07 \: ms {}^{ - 2}}}}$ For Calculating Distance, $\huge\pink{s = ut + \frac{1}{2} at {}^{2} }$ $\large{s = 2.7 \times 120 + \frac{1}{2} \times 0.07 \times 120 \times 120}$ $\large{s = 324 + 504}$ $\huge\green{\boxed{\purple{s = 828 \: meter}}}$ $\huge\pink{\underline{\underline{\mathbb{\orange{BrAInLIesT}}}}}$