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A train travelling with a velocity 72kmph reaches the station in 5 minutes. Assuming that the acceleration is uniform, find (a) the acceleration and (b) the distance travelled by the train before reaching the station. |
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Answer» speed=72×5/18=20m/st=5×60=300sa=20/300=1/15=0.066m/s²distance=20×300=6000m=6km |
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