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A train travelling at 36km/have access template unit formal at 2m/s2 cal. It velocity after 5 sec |
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Answer» v=20m/s Explanation: Given- u=36km/h =36×5/18 =10m/s a=2m/s^2 t=5sec v=? v=u+at v=10+2×5 v=20m/s |
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