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a train traveling at 20ms accelerates at0.5ms calculate the time interval in which it covers distance of 825m |
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Answer» In order to ANSWER this question, we must apply newton's first equation of motion v = u + at Where v is the final velocity in m/s, which is we shall attempt to find, u is the initial velocity in m/s, given in the question as 20m/s a is the acceleration of the body in m/s2, in the question, it is indicated to be 4m/s2 t is the time in SECONDS, from the question, it is 4s. v = 20 + 4*4 v = 20 + 16 = 36m/s As for the distance, either the second or third equation of motion can be used. Using the second equation, s (distance) = u*t + 0.5*a*(t^2) s = 20*4 + 0.5*4*(4*4) s = 80 + 32 = 112m Using the third equation of motion, v2 = U2 + 2as 36^2 = 20^2 + 2*4*s 1296 = 400 + 8 * s 8*s = 1296 - 400 = 896 s = 896/8 = 112mExplanation: |
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