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a train starts from rest and accelerates uniformly at a rate and accelerates uniformly at a rate of 2 metre per second square for 15 seconds then sentences constant velocity for 300 seconds it then experiences a uniform retardation manth brakes are applied and comes to rest in 15 seconds find the maximum velocity reached the retardation the total distance travelled and the average velocity of the train |
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Answer» istance covered(s) = Distance during ACCELERATION(s 1 ) + distance during uniform motion(s 2 ) + distance during RETARDATION(s 3 )For acceleration,v=u+a∗tv max =2×10=20 m/ss=ut+(1/2)at 2 s 1 =(1/2)×2×10 2 =100 m |
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