1.

a train starting from stationary position and moving with uniform acceleration attends a speed of 36 km per hour and 10 minutes find acceleration

Answer»

If a train starts from stationary position then initial velocity of train = 0 
moving uniform acceleration MEANS constant acceleration .
given , FINAL velocity ( V) = 36 km/h = 36× 5/18 = 10m/s 
TIME taken = 10 minutes = 10× 60sec = 600sec 
USE KINEMATICS equation , 
V = u + at 
10 = 0 + a × 600 
a = 10/600 = 1/60 m/s² 
a = 0.1667 × 10^-1 m/s² = 1.67 × 10^-2 m/s² 



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