A train starting from rest attains a velocity of 72 km/h in 5minutes . Assuming that the acceleration in uniform find (a) the acceleration (b) the distance travelled by the train for attaining the velocity?

A train starting from rest attains a velocity of 72 km/h in 5minutes .

1.	A train starting from rest attains a velocity of 72 km/h in 5minutes . Assuming that the acceleration in uniform find (a) the acceleration (b) the distance travelled by the train for attaining the velocity?
Answer» Velocity of TRAIN = 72 km/hr = 72 × 5 / 18 m/s = 4 × 5 m/s = 20 m/sAcceleration = velocity / timeTime = 5 min = 5 × 60 s = 300 sAcceleration = 20 m/s / 300 s = 1/15 m/s² = 0.0666 m/s²ANSWER:The ACCELERATION is 0.067 m/s²Distance TRAVELED Velocity = 20 m/sSo in 1 s , the train travels 20 mIn 5 min , the train will travel 20 m × 5 × 60= 100 × 60 m= 6000 mANSWER:The distance traveled is 6000 m.

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A train starting from rest attains a velocity of 72 km/h in 5minutes . Assuming that the acceleration in uniform find (a) the acceleration (b) the distance travelled by the train for attaining the velocity?

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