A train starting from rest attains a velocity of 72 km/h in 5 minutes.

1.	A train starting from rest attains a velocity of 72 km/h in 5 minutes. Assuming that the acceleration is uniform, find 1. The acceleration 2. The distance travelled by the train for attaining this velocity.
Answer» V=U+at a=(v-u)/t -----------(1) v=72 km/h =20m/s u=0 t=5*60 sec =300sec by putting VALUES of v,u,t in (1) a=1/15 m/s2 s=ut +(1/2)at2 =0+(1/2)(1/15)(300)(300) =3km

A train starting from rest attains a velocity of 72 km/h in 5 minutes. Assuming that the acceleration is uniform, find 1. The acceleration 2. The distance travelled by the train for attaining this velocity.

Answer»

V=U+at

a=(v-u)/t -----------(1)

v=72 km/h

=20m/s

u=0

t=5*60 sec =300sec

by putting VALUES of v,u,t in (1)

a=1/15 m/s2

s=ut +(1/2)at2

=0+(1/2)(1/15)(300)(300)

=3km

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A train starting from rest attains a velocity of 72 km/h in 5 minutes. Assuming that the acceleration is uniform, find 1. The acceleration 2. The distance travelled by the train for attaining this velocity. ​

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A train starting from rest attains a velocity of 72 km/h in 5 minutes. Assuming that the acceleration is uniform, find 1. The acceleration 2. The distance travelled by the train for attaining this velocity.