A train running at 7/11 of its own speed reached a place in 22 hrs. Ho

1.	A train running at 7/11 of its own speed reached a place in 22 hrs. How much time could be saved if the train runs at its own speed?1. 7 hrs2. 8 hrs3. 14 hrs4. 16 hrs
Answer» Correct Answer - Option 2 : 8 hrs Given: The new speed of the train = 7/11 × old speed of the train With new speed, time taken to reach the place = 22 hours Concept used: When traveling the same distance, Speed ∝ (1/time) Calculation: Let the old speed be S_O and the new speed be S_N Let the old time taken be T_O and new time taken be T_N SN = (7/11) × SO ⇒ S_N ∶ S_O = 7 ∶ 11 ⇒ T_N ∶ TO = 11 ∶ 7 With new speed, time taken to reach, T_N = 11x = 22 hrs ⇒ x = 2 hrs The time that could be saved by him if the train runs on time = 11x – 7x = 4x ⇒ 4x = 4 × 2 = 8 hours. ∴ The time that can be saved by running with old speed is 8 hours.

A train running at 7/11 of its own speed reached a place in 22 hrs. How much time could be saved if the train runs at its own speed?1. 7 hrs2. 8 hrs3. 14 hrs4. 16 hrs

Answer» Correct Answer - Option 2 : 8 hrs

Given:

The new speed of the train = 7/11 × old speed of the train

With new speed, time taken to reach the place = 22 hours

Concept used:

When traveling the same distance,

Speed ∝ (1/time)

Calculation:

Let the old speed be S_O and the new speed be S_N

Let the old time taken be T_O and new time taken be T_N

SN = (7/11) × SO

⇒ S_N ∶ S_O = 7 ∶ 11

⇒ T_N ∶ TO = 11 ∶ 7

With new speed, time taken to reach, T_N = 11x = 22 hrs

⇒ x = 2 hrs

The time that could be saved by him if the train runs on time = 11x – 7x = 4x

⇒ 4x = 4 × 2 = 8 hours.

∴ The time that can be saved by running with old speed is 8 hours.

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