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A train passes a standing man in 3 seconds and a platform 105m long in 8 secomds.Find the lenght of the train and itd speed |
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Answer» speed=315 m/slength of train=63 mExplanation:take LENGTH of train as xx=3v105+x=8vv=(105+x)/3=x/8v=105/8=5x/24using CROSS MULTIPLICATION,v=315=5xspeed=315m/sx=315/5 =63 mhope it helped and pls MARK as BRAINLIEST:) |
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