A train of mas 6xx10^(2) metric tons is pulled by a loco-motive of mass 150 metric ton. The speed of the train is 54 kmph. The locomotive pulls the train on the level track. The force of friction on the locomotive and the train is 10 N per metric ton. Calculate the power of the locomotive.

A train of mas 6xx10^(2) metric tons is pulled by a loco-motive of mas

1.	A train of mas 6xx10^(2) metric tons is pulled by a loco-motive of mass 150 metric ton. The speed of the train is 54 kmph. The locomotive pulls the train on the level track. The force of friction on the locomotive and the train is 10 N per metric ton. Calculate the power of the locomotive.
Answer» Solution :GIVEN, mass of TRAIN, `m_(1)=6xx10^(2)" METRIC tons"=6xx10^(2)xx10^(3) kg` Mass of locomotive, `m_(2)=150" metric tons"=150xx10^(3) kg` Force of friction= 10 N/metric ton. Speed of the train=54 kmph `=54xx5/18ms^(-1)=15ms^(-1)` TOTAL mass moving`=m_(1)+m_(2)=600+150=750" metric tons"=750xx10^(3)kg` Total frictional force, `f=(10N//"metric ton") 750" metric ton"=10xx750N=7500N` Power of engine = `fv=7500xx15W=1125xx100W=112.5 kW`