A train met with an accident50km away from Ananipurstation. It complet

1.	A train met with an accident50km away from Ananipurstation. It completed the remaining journey at s'n of theprevious epeed and reachedBar mala station how 12 inlate. Had accident taken place60 km further it would havebeen only 3 hourjoie1) What is the normal speed oftrain ?in what is the distance betweenAnantpur and Barmula 2
Answer» I PROMISE I WILL FOLLOW YOU IF YOU MARK AS BRAINLIST THANKS FOR QUESTION YOUR ANSWER IS Train proceeds at 3/4 S where S is his usual speed means 1/4 decrease in the speed which will lead to 1/3 increase in the time. [ As S T = D, Speed is inversely proportional to time when DISTANCE is constant]. Now, the main difference come in those 24 km and the change in difference of time = 35 - 25 = 10 m = 1 / 3 T = 10 where T is the time required to cover the distance of (50 - 74) = 24 km T = 30 min = 0.5 hours Speed of the train = 24 / (0.5) = 48 kmph

A train met with an accident50km away from Ananipurstation. It completed the remaining journey at s'n of theprevious epeed and reachedBar mala station how 12 inlate. Had accident taken place60 km further it would havebeen only 3 hourjoie1) What is the normal speed oftrain ?in what is the distance betweenAnantpur and Barmula 2

Answer»

I PROMISE I WILL FOLLOW YOU IF YOU MARK AS BRAINLIST

THANKS FOR QUESTION

YOUR ANSWER IS

Train proceeds at 3/4 S where S is his usual speed means 1/4 decrease in the speed which will lead to 1/3 increase in the time.

[ As S *T = D, Speed is inversely proportional to time when DISTANCE is constant].

Now, the main difference come in those 24 km and the change in difference of time = 35 - 25 = 10 m

= 1 / 3 *T = 10 where T is the time required to cover the distance of (50 - 74) = 24 km

T = 30 min = 0.5 hours

Speed of the train = 24 / (0.5) = 48 kmph

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