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A train is travelling at a speed of 90 km per hour .breaks are applied so as to produce a uniform acceleration of 0. negative 5 metre per second . find thow far the train will go before it goes to rest? |
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Answer» v=u+at 90km/hr=90*1000/3600m/s=25m/s 0=25-0.5t t=50s s=ut+0.5at^2 s=25*50-0.5*0.5*50^2 s=1250-625 s=625m |
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