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A train is traveling at a speed of 90 km h(power -1).Brakes r applied so as to produce a uniform accelaration of -0.5 m s (power -2).Find how far the train will go before it is brought to rest. |
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Answer» kmph = 90 * 5/18 m/sec = 25 m/seca = -0.5 m/sec²v = 0 as the train COMES to rest.the equation of motion is v² = u² + 2 a s 0 = 25² - 2 * 0.5 * s s = 625 METERS |
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