1.

a train is moving with velocity 30 metre per second comes to rest after covering a distance of 2800 metre calculate its acceleration​

Answer»

Answer:

-0.16 m/s

Explanation:

Use EQUATION of motion

a = (v² - u²) / (2S)

= (0² - 30²) / (2 × 2800)

= -900/5600 m/s²

= -0.16 m/s

Negative SIGN indicates that it's RETARDATION.



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