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a train is moving with velocity 30 metre per second comes to rest after covering a distance of 2800 metre calculate its acceleration |
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Answer» Answer: -0.16 m/s Explanation: Use EQUATION of motion a = (v² - u²) / (2S) = (0² - 30²) / (2 × 2800) = -900/5600 m/s² = -0.16 m/s Negative SIGN indicates that it's RETARDATION. |
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