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A train is moving with a velocity of 90km/hIt is brought to stop by applying the brakeswhich produce a retardation of 0.5 m/sFind:1) velocity after 30s, and2)the time taken by thetrain to come to rest. |
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Answer» Answer: Equation to be applied " v = U - a×t ", v is final velocity, u is initial velocity, a is retardation and t is time.
Velocity at the time of applying break = 90 km/h = 90 km/h × (5/18) = 25 m/s
(1) velocity after 30 s :- v = 25-(1/2)×30 = 19 m/s
(2) time to come to rest :- 0 = 25-(1/2)×t , SOLVING for t , we get t = 50 s |
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