1.

A train is moving with a velocity of 90km/hIt is brought to stop by applying the brakeswhich produce a retardation of 0.5 m/sFind:1) velocity after 30s, and2)the time taken by thetrain to come to rest.​

Answer»

Answer:

Equation to be applied  " v = U - a×t ", v is final velocity, u is initial velocity, a is retardation and t is time.

Velocity at the time of applying break = 90 km/h  = 90 km/h × (5/18) = 25 m/s

(1) velocity after 30 s :-   v = 25-(1/2)×30 = 19 m/s

(2) time to come to rest :-  0 = 25-(1/2)×t  , SOLVING for t ,  we get  t = 50 s



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