A train is moving with a velocity of 90 kmh-1 .It is brought to stop by applying the brakes which produces a retardation of 0.5 ms-2. Find:a) The velocity after 10 s.b) The time taken by train to come to rest.

A train is moving with a velocity of 90 kmh-1 .It is brought to stop

1.	A train is moving with a velocity of 90 kmh-1 .It is brought to stop by applying the brakes which produces a retardation of 0.5 ms-2. Find:a) The velocity after 10 s.b) The time taken by train to come to rest.
Answer» train is moving with a velocity of 90 kmh-1.It is brought to stop by applying the BRAKES which produces a RETARDATION of 0.5 ms-2To FINDA) The velocity after 10 s.b) The time taken by train to come to rest.SolutionInitial velocity = 90km/hAcceleration = -0.5 m/s²Velocity after 10s = ?→ u = 90m/s → u = 90 × 5/18 → u = 25m/sAccording to the first equation of motion→ v = u + at→ v = 25 + (-0.5) × 10→ v = 25 - 5→ v = 20m/sVelocity after 10s is 20m/sTotal taken to come in rest = ?Final velocity = 0 {brakes applied}→ v = u + at→ 0 = 25 + (-0.5) × t→ - 25 = -0.5t→ t = 25/0.5 = 50sTime taken to come in rest is 50sNote : (-) MINUS shows retardation

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A train is moving with a velocity of 90 kmh-1 .It is brought to stop by applying the brakes which produces a retardation of 0.5 ms-2. Find:a) The velocity after 10 s.b) The time taken by train to come to rest.​

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A train is moving with a velocity of 90 kmh-1 .It is brought to stop by applying the brakes which produces a retardation of 0.5 ms-2. Find:a) The velocity after 10 s.b) The time taken by train to come to rest.