1.

A train is moving with a velocity of 18 km/h in 5 mins. Find itsacceleration and distance covered by the train

Answer»

Explanation:

Given :-

  • Initial VELOCITY u = 0
  • Final Velocity v= 18 km/hr = 5 m/s
  • Time t = 5 min = 300 sec
  • Distance S = ?
  • Acceleration a = ?

Using First EQUATION of MOTION

  • v = u + at
  • 5 = 0 + a × 300
  • a = 5 / 300 = 0.016 m/s²

Using Second equation of motion

  • S = UT + 1/2 at²
  • S = 0 × 300 + 1/2 × 0.016 × (300)²
  • S = 1/2 × 0.016 × 300 × 300
  • S = 750 m


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