1.

A train accelerates uniformly from 18 km/h to 36 km/h in 10 s. Find the distance traveled.

Answer» U = 18 km/h = 18×5/18 = 5 m/s v = 36 km/h = 36×5/18 = 10 m/s t = 10 s v = u+at 10 = 5 + 10a 10a = 10-5 10a = 5 a = 5/10 a = 0.5 m/s² s = ut + 1/2at² = 5×10+1/2×0.5×10² = 50+0.25×100 = 50+25 = 75 m


Discussion

No Comment Found

Related InterviewSolutions