1.

A train accelerates from 36 km/h to 54 km/h in 10 sec.(i) Acceleration (ii) The distance travelled by car.

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Given :-

U = 36 km/h = 36 \times\frac{1000}{60 \times 60} = 10 m/s

V = 54 km/h = 36 \times\frac{1000}{60 \times 60} = 15 m/s

T = 10 s

A = ?

S = ?

Let's FIND the 1 ACCELERATION :

A = \frac{V - U}{T}

A = \frac{15 - 10}{10}

A = 0.5 m/{s}^{2}

Let's find the DISTANCE :

S = UT + \frac{1}{2}\:A {T}^{2}

S = 10 + 10 \frac{1}{2}×\:0.5× {10}^{2}

S = 20 + 5

S = 25 m


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