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A train accelerates from 36 km/h to 54 km/h in 10 sec.(i) Acceleration(ii) The distance travelled by car. |
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Answer» (i) a = (v-u)/t = (54-36)/10 = 18/10 = 1.8m/s² (II) s = ut+1/2at² = (36×10)+1/2×1.8×10² = 360 + 1/2×1.8×100 = 360 + 90 = 450m |
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