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A train accelerates from 36 kilometre are 254 kilometre are in 10 seconds find |
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Answer» tion:GIVEN:Initial velocity= 36km/h-36x5/18=10m/sFinal velocity =54km/h-54x5/18=15m/sTime =10secAcceleration = v-u/ t-15-10/10=5/10-1/2-0.5 m/s2Distance =s=?From second equation of motion:S=ut +1/2 at^2=10*10+1/2*0.5*10*10=100+25=125mSo DISTANCE travelled is 125M |
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