A train 300 m long passes a pole in 15 seconds and crosses another tra

1.	A train 300 m long passes a pole in 15 seconds and crosses another train of the same length traveling in the opposite direction in 8 seconds. Calculate the speed of the other train in km/h.1. 200 km/h2. 198 km/h3. 190 km/h4. 222 km/h5. None of the above
Answer» Correct Answer - Option 2 : 198 km/h Length of train = 300 m Time is taken by train to pass a pole = 15 seconds Time taken to cross another train of the same length = 8 seconds Calculations: Speed of the 1^st train = 300/15 = 20 m/s Let the speed of 2^nd train be x Relative speed = (20 + x) m/s Length of 1^st train + length of 2^nd train = 300 + 300 = 600 m In the second scenario the equation is ⇒ 600/(20 + x) = 8 ⇒ 600 = 160 + 8x ⇒ 600 – 160 = 8x ⇒ 440 = 8x ⇒ x = 55 m/s ∴ Speed of the train = 55 × 18/5 = 198 km/h. The speed of the train is 198 km/h.

A train 300 m long passes a pole in 15 seconds and crosses another train of the same length traveling in the opposite direction in 8 seconds. Calculate the speed of the other train in km/h.1. 200 km/h2. 198 km/h3. 190 km/h4. 222 km/h5. None of the above

Answer» Correct Answer - Option 2 : 198 km/h

Length of train = 300 m

Time is taken by train to pass a pole = 15 seconds

Time taken to cross another train of the same length = 8 seconds

Calculations:

Speed of the 1^st train = 300/15 = 20 m/s

Let the speed of 2^nd train be x

Relative speed = (20 + x) m/s

Length of 1^st train + length of 2^nd train = 300 + 300 = 600 m

In the second scenario the equation is

⇒ 600/(20 + x) = 8

⇒ 600 = 160 + 8x

⇒ 600 – 160 = 8x

⇒ 440 = 8x

⇒ x = 55 m/s

∴ Speed of the train = 55 × 18/5 = 198 km/h.

The speed of the train is 198 km/h.

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