A train 200 m long enters at 5 m/s and exits at 3 m/s from a bridge 30

1.	A train 200 m long enters at 5 m/s and exits at 3 m/s from a bridge 300 m long.The time taken by it is
Answer» Answer: 2 minutes 5 SECOND Explanation: Total distance S = 200 + 300 = 500m Initial velocity U = 3m/s Final velocity V = 5 m/s We know, v² - u² = 2AS => 25 - 9 = 1000a => a = (16/1000)m/s² Again v = u + at => 5 = 3 + (16/1000)t => t = 2 × (1000/16) = 125 s = 2 minutes 5 second

A train 200 m long enters at 5 m/s and exits at 3 m/s from a bridge 300 m long.The time taken by it is

Answer»

Answer:

2 minutes 5 SECOND

Explanation:

Total distance S = 200 + 300 = 500m

Initial velocity U = 3m/s

Final velocity V = 5 m/s

We know,

v² - u² = 2AS

=> 25 - 9 = 1000a

=> a = (16/1000)m/s²

Again

v = u + at

=> 5 = 3 + (16/1000)t

=> t = 2 × (1000/16) = 125 s = 2 minutes 5 second

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A train 200 m long enters at 5 m/s and exits at 3 m/s from a bridge 300 m long.The time taken by it is

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