A train 108 m long moving at a speed of 50 km/hr crosses a train 112 m

1.	A train 108 m long moving at a speed of 50 km/hr crosses a train 112 m long coming from the opposite direction in 6 seconds. What is the speed of the second train?
Answer» Let the speed of the second train be x km/hr. Then, Relative speed of trains = (\(x\) + 50) km/hr = (\(x\) + 50) x \(\frac{5}{18}\) m/s Total time taken = \(\frac{\text{Sum of lengths of both the trains}}{\text{Relative speed}}\) = \(\frac{108\,m\,+112\,m}{(x\,+50)\times\frac{5}{18}}\) ⇒ \(\frac{220\times18}{(x\,+50)\times5}\) = 6 ⇒ 44 × 3 = x + 50 ⇒ 132 = x + 50 ⇒ x = 132 – 50 = 82 km/hr.

A train 108 m long moving at a speed of 50 km/hr crosses a train 112 m long coming from the opposite direction in 6 seconds. What is the speed of the second train?

Answer»

Let the speed of the second train be x km/hr. Then,

Relative speed of trains = (\(x\) + 50) km/hr

= (\(x\) + 50) x \(\frac{5}{18}\) m/s

Total time taken = \(\frac{\text{Sum of lengths of both the trains}}{\text{Relative speed}}\)

= \(\frac{108\,m\,+112\,m}{(x\,+50)\times\frac{5}{18}}\)

⇒ \(\frac{220\times18}{(x\,+50)\times5}\) = 6

⇒ 44 × 3 = x + 50 ⇒ 132 = x + 50 ⇒ x = 132 – 50 = 82 km/hr.

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A train 108 m long moving at a speed of 50 km/hr crosses a train 112 m long coming from the opposite direction in 6 seconds. What is the speed of the second train?

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