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| 1. |
A toycart is designed in sucha way that aftermoving 500 cm forward it reversed 300 cmback at a rateof 100 cm per five seconds. Findthe timetaken by the cart to covera distanceof 1 m. |
| Answer» Solution :To coverthe distanceof 1m,the cart will ACTUALLY COVER ` 5 xx 500 + 5 xx 300 = 4000` CM = 40 .Timetaken to cover the distanceof 4000 cm will be 200 seconds. | |