A tower stands vertically on the ground. from a point which is 15 m aw

1.	A tower stands vertically on the ground. from a point which is 15 m away from the foot of the tower , the angle of elevation of the top of the tower is 45°.what is the height of the tower
Answer» Angle of ELEVATION = 45 Then, 15M/HEIGHT of tower = tan45 15m/height of tower = 1 Height of the tower = 15m OR Since the angle is 45 The right triangle formed by the tower and the point on the ground has ONE angle to be 45 degrees So, it is an isosceles right triangle Therefore, DISTANCE from tower = Height of tower = 15m

A tower stands vertically on the ground. from a point which is 15 m away from the foot of the tower , the angle of elevation of the top of the tower is 45°.what is the height of the tower

Answer»

Angle of ELEVATION = 45

Then,

15M/HEIGHT of tower = tan45

15m/height of tower = 1

Height of the tower = 15m

Since the angle is 45

The right triangle formed by the tower and the point on the ground has ONE angle to be 45 degrees

So, it is an isosceles right triangle

Therefore,

DISTANCE from tower = Height of tower = 15m

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A tower stands vertically on the ground. from a point which is 15 m away from the foot of the tower , the angle of elevation of the top of the tower is 45°.what is the height of the tower

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