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A torch bulb rated `4.5 W, 1.5 V` is connected as shown in Fig. 7.35. The emf of the cell needed to make the bulb glow at full intensity is A. `4.5 V`B. `1.5 V`C. `2.67 V`D. `13.5 V` |
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Answer» Correct Answer - D (d) Current in the bulb `= (P).(V) = (4.5)/(1.5) = 3 A` Current in `1 Omega` resistance `= (1.5)/(1) = 1.5 A` Hence total current from the cell `i= 3 + 1.5 = 4.5 A` By using `E = V + ir implies E 1.5 + 4.5 xx (2.67) = 13.5 V)` |
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