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A torch bulb is rated 5V and 500mA. Calculate its (i) power, (ii) resistance, (iii) energyconsumed when it is lighted for 4 hours. |
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Answer» Step-by-step explanation: GIVEN, i= 500mA V= 5V (i) power=VI =5× 500 ×0.001 =2.5 WATT (ii) V=IR R=5÷(500×0.001) =10 ohm (iii) Energy dissipated as heat will be H=VIt =5×500×0.001×4×60×60 =36000 joule. |
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