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A tightly-wound, long solenoid having 50 turns/cm, Carries a current of 4.00 A. Find the magnetic intensity Hand the magnetic field B at the centre of the solenoid. What will be the values of these quantities if an iron core is inserted in the solenoid and the magnetization l in the core is 4.00 xx 10^(6) A/m? |
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Answer» Solution :The magnetic intensity H at the CENTRE of a long solenoid is H = ni `=50xx10^(2)m^(-1)xx4A=2xx10^(4)A//m` The magnetic FIELD `B = μ_(0)H` `=4pixx10^(-7)T-m//Axx2xx10^(4)A//m` `=8pixx10^(-3)T=25mT` The value ofH does not change as the iron core is inserted and remains `2xx10^(4)A//m`. The magnetic field B becomes `B=mu_(0)(H+I)=(4pixx10^(-7)t-m//A)(2xx10^(4)+4XX10^(6))A//m=5.05T` It should be noted that the magnetic intensity H is very small as COMPARED to the MAGNETIZATION I in presence of the iron core. |
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