1.

A three phase Y connected balancedload is connected by 400V,50 Hz 3phase supply. The impedance of eachphase is 10 ohm. What is the totalthree phase power?​

Answer»

Answer:

Y connection, voltage applied across each impedance = 400/√3 so PHASE current = V/Z=400/10√3= 40/√3 amps

Power in each phase = Phase voltage X phase current = 400/√3 x 40/√3 = 1600/3 VA

Total power(THREE PHASES) = 1600/3 × 3 =1600 VA or 1.6 kVA

Active power can be CALCULATED if load angle of 10 ohm impedance is known



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