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A three phase Y connected balanced load is connected by 400V,50 Hz 3phase supply. The impedance of eachphase is 10 ohm. What is the totalthree phase power? |
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Answer» ong>Answer: Y connection, voltage applied ACROSS each impedance = 400/√3 so phase current = V/Z=400/10√3= 40/√3 amps
Power in each phase = Phase voltage X phase current = 400/√3 x 40/√3 = 1600/3 VA
TOTAL power(three phases) = 1600/3 × 3 =1600 VA or 1.6 kVA
Active power can be calculated if load angle of 10 ohm impedance is known |
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